5m^2-(5/4)=0

Solution for 5m^2-(5/4)=0 equation:

5m^2-(5/4)=0

We add all the numbers together, and all the variables

5m^2-(+5/4)=0

We get rid of parentheses

5m^2-5/4=0

We multiply all the terms by the denominator


5m^2*4-5=0

Wy multiply elements

20m^2-5=0

a = 20; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·20·(-5)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*20}=\frac{-20}{40}
=-1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*20}=\frac{20}{40}
=1/2
$